7y^(1/2)+2y+3=0

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Solution for 7y^(1/2)+2y+3=0 equation: 


D( y )

y < 0

y < 0

y in <0:+oo)

2*y+7*y^(1/2)+3 = 0

t_1 = y^(1/2)

2*t_1^2+7*t_1^1+3 = 0

2*t_1^2+7*t_1+3 = 0

DELTA = 7^2-(2*3*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-7)/(2*2) or t_1 = (-25^(1/2)-7)/(2*2)

t_1 = -1/2 or t_1 = -3

t_1 = -3

y^(1/2)+3 = 0

1*y^(1/2) = -3 // : 1

y^(1/2) = -3

( -3 < 0 i 1/2 in (0:1) ) => y naleu017Cy do O

t_1 = -1/2

y^(1/2)+1/2 = 0

1*y^(1/2) = -1/2 // : 1

y^(1/2) = -1/2

( -1/2 < 0 i 1/2 in (0:1) ) => y naleu017Cy do O

y belongs to the empty set

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